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Older gdb used to default to assuming that a symbol was an int when it didn't have debug info describing the size / type (gdb) set (int) constant = 666 left operand of assignment is not an lvalue. This generally caused more confusion than the current behaviour, so it was changed.
When gdb doesn't have access to glibc debugging information, it won't have access to type information for errno and __errno_location, which is the function that, when called, returns the address of errno storage for the current thread. But when i put the (int) declarator i get After we compile, launch gdb, and step into main, let’s ask gdb to tell us the types of the variables a, b, and c.
For the expressions you use in gdb commands, you can tell gdb to not enforce strict type checking or to treat any mismatches as errors and abandon the expression
When type checking is disabled, gdb successfully evaluates expressions like the second example above. I'm encountering an issue while debugging nasm assembly code using gdb The error message i receive is (gdb) print num 'num' has unknown type
To reproduce the bug, set the breakpoint to t.d:10 and examine the `i` global variable (using `p t.i`) Gdb will then complain that 't.i' has unknown type The developer may not know the mangled variable name. Gdb circumvents the problem by considering the symbol to have the name foo, which may cause other problems if many symbols end up with this name
Unknown symbol type 0xnn the symbol information contains new data types that gdb does not yet know how to read
0xnn is the symbol type of the uncomprehended information, in hexadecimal. First, gdb points out i need to declare variable's type (gdb) set constant = 666 'constant' has unknown type Cast it to its declared type no problem, i go for (int) (as with the print command)
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