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The first way works for a list or a string How can i list all files of a directory in python and add them to a list? The second way only works for a list, because slice assignment isn't allowed for strings
Other than that i think the only difference is speed The second action taken was to revert the accepted answer to its state before it was partway modified to address determine if all elements in one list are in a second list. It looks like it's a little faster the first way
Try it yourself with timeit.timeit () or preferably timeit.repeat ().
If it was public and someone cast it to list again, where was the difference Don't use quotes on the command line 1 don't use type=list, as it will return a list of lists this happens because under the hood argparse uses the value of type to coerce each individual given argument you your chosen type, not the aggregate of all arguments You can use type=int (or whatever) to get a list of ints (or whatever) If your list of lists comes from a nested list comprehension, the problem can be solved more simply/directly by fixing the comprehension
Please see how can i get a flat result from a list comprehension instead of a nested list? The most popular solutions here generally only flatten one level of the nested list See flatten an irregular (arbitrarily nested) list of lists for solutions that. I want to get a list of the column headers from a pandas dataframe
The dataframe will come from user input, so i won't know how many columns there will be or what they will be called
Since a list comprehension creates a list, it shouldn't be used if creating a list is not the goal So refrain from writing [print(x) for x in range(5)] for example. A list uses an internal array to handle its data, and automatically resizes the array when adding more elements to the list than its current capacity, which makes it more easy to use than an array, where you need to know the capacity beforehand. The implementation uses a contiguous array of references to other objects, and keeps a pointer to this array
This makes indexing a list a [i] an operation whose cost is independent of the size of the list or the value of the index When items are appended or inserted, the array of references is resized.
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