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As far as i know, what you're trying to do (use if statement and then return a value from a macro) isn't possible in iso c.but it is somewhat possible with statement expressions (gnu extension) #ifndef debug #define printd // #else #define printd printf #endif is there a. I've found that this works on gcc and clang by default:
What is the point of #define in c++ What i wanted to accomplish is something like this I've only seen examples where it's used in place of a magic number but i don't see the point in just giving that value to a variable instead.
The #define directive is a preprocessor directive
The preprocessor replaces those macros by their body before the compiler even sees it Think of it as an automatic search and replace of your source code A const variable declaration declares an actual variable in the language, which you can use.well, like a real variable Take its address, pass it around, use it, cast/convert it, etc
How do i define a function with optional arguments Asked 13 years, 9 months ago modified 1 year, 5 months ago viewed 1.2m times So i read the interesting answers about what are the differences between constexpr and const but i was curious about are the differences between #define and constexpr I feel like constexpr is jus.
I have been seeing code like this usually in the start of header files
#ifndef headerfile_h #define headerfile_h and at the end of the file is #endif what is the purpose of this? #define _add_penguin(a) penguin ## a #define add_penguin(a) _add_penguin(a) #define width (100) #define height 200 add_penguin(height) // expands to penguin200 add_penguin(width) // error, cannot concatenate penguin and (100) same for stringization (#) Clearly this is a corner case and probably doesn't matter considering how width will presumably be used Still, it is something to keep in.
How can i use #if inside #define in the c preprocessor Asked 15 years, 6 months ago modified 8 months ago viewed 51k times I'm trying to do a debug system but it seems not to work
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