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Super() is a special use of the super keyword where you call a parameterless parent constructor Super tells you what you can put into the class (at most this, perhaps a superclass) In general, the super keyword can be used to call overridden methods, access hidden fields or invoke a superclass's constructor.
Super() lets you avoid referring to the base class explicitly, which can be nice The distinction is important because extends tells you what you can get out of a class (you get at least this, perhaps a subclass) But the main advantage comes with multiple inheritance, where all sorts of fun stuff can happen.
The one with super has greater flexibility
The call chain for the methods can be intercepted and functionality injected. In fact, multiple inheritance is the only case where super() is of any use I would not recommend using it with classes using linear inheritance, where it's just useless overhead. As for chaining super::super, as i mentionned in the question, i have still to find an interesting use to that
For now, i only see it as a hack, but it was worth mentioning, if only for the differences with java (where you can't chain super). 'super' object has no attribute '__sklearn_tags__' This occurs when i invoke the fit method on the randomizedsearchcv object I attempted to tune the hyperparameters of an xgbregressor.
I'm currently learning about class inheritance in my java course and i don't understand when to use the super() call
I found this example of code where super.variable is used If you add any other column/attribute to a primary key then it become a super key, like employeeid + fullname is a super key If a table don't have any individual columns that qualifies for a candidate key, then you have to select 2 or more columns to make a row unique. If we're using a class method, we don't have an instance to call super with
Fortunately for us, super works even with a type as the second argument Which is exactly what python tells me is not possible by saying that do_something () should be called with an instance of b. Super in generics is the opposite of extends Instead of saying the comparable's generic type has to be a subclass of t, it is saying it has to be a superclass of t
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